FIX: Bitwise shift operators return incorrect results when you run a Visual C++ application that is developed in Visual Studio 2010

#include "stdafx.h"
 
typedef unsigned long long uint64;
 
void print(uint64 bitBoard) 
{
    printf("bitboard: %llu\n", bitBoard);
 
    for (int i = 0 ; i < 1; i++) 
       {
        // If either of the following two statements is commented out, the running results are correct.
        printf("bitBoard before shift down: %llu\n", bitBoard); 
        bitBoard >>= 8;
       }
}
 
 
 
int main() 
{
    for (int square = 31; square <= 32; square++) 
       {
        printf("When square is: %d\n", square);
 
        printf("\n(Case A):\n");
        uint64 temp = uint64(1) << square;
        print(temp);
 
        printf("\n(Case B): \n");
        print((uint64)(uint64(1LU) << square));
 
        printf("\n(Case C):\n");
        print((uint64)(uint64(1) << square));
 
        printf("\n(Case D): \n");
        print(1ULL << square);
 
        // Workaround method is using the following statement instead.
        //print(1ULL << (uint64)square);
 
        printf("\n");
    }
}