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In all following examples, the UserForm being used is called "UserForm1".
In Microsoft Excel 2000, if you want a Visual Basic macro to display
UserForm1, the line of code would be:
Although this syntax is very simple, it can cause problems if you want to
show a UserForm whose name is stored in a variable. For example, if the
variable
x contains the name of the UserForm, you cannot simply use the following to display UserForm1.
Sub Test()
x = "UserForm1"
x.Show
End Sub
If you run this macro, you receive the following error message:
Run-time error '424'
Object Required
UserForm Name Stored in a Variable
If you want to show a UserForm whose name is stored in a variable,
use the following code:
Sub ShowUserForm1()
X = "UserForm1"
VBA.UserForms.Add(X).Show
End Sub
User Prompted for UserForm Name
You can use the
InputBox method to ask users what UserForm they want to show:
Sub ShowUserForm2()
X = InputBox("Show which UserForm?: ")
VBA.UserForms.Add(X).Show
End Sub
UserForm Name Retrieved from Worksheet Cell
You can read a value from a cell in a worksheet:
Sub ShowUserForm3()
'Cell A1 of Sheet1 contains the name of the UserForm
X = ActiveWorkbook.Sheets("Sheet1").Cells(1, 1).Value
VBA.UserForms.Add(X).Show
End Sub
Prompt for Index Number to Display UserForm
You can include a list of UserForm names in your macro and set the value of
x to the UserForm that corresponds to an index number.
NOTE: The following example assumes you have three UserForms in your project:
UserForm1, UserForm2, and UserForm3. You may want to insert some macro code
to make sure the value entered is between 1 and 3, inclusive.
Sub ShowUserForm4()
'Display an input box asking for a number between 1 and 3
'(inclusive).
Y = Application.InputBox (Prompt:="enter 1, 2, or 3", Type:=1)
'Based on the number entered in the input box, X will be set to
'the appropriate string.
Select Case Y
Case 1
X = "UserForm1"
Case 2
X = "UserForm2"
Case Else
X = "UserForm3"
End Select
VBA.UserForms.Add(X).Show
End Sub
In each case above, the UserForm you want to show must exist. If it does
not exist in your project, you will receive the following error message and your macro will stop.